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bd40bc7c7a Again, the vast majority of that was identical to the previous section as well. Now, the integral left is nothing more than the integral that we would need to compute if we were going to find the Laplace transform of f(t). You can access the Site Map Page from the Misc Links Menu or from the link at the bottom of every page. In the last interval, all three Heaviside function are one and the function has the value. Let me know what page you are on and just what you feel the typo/mistake is. Here's why. Put Internet Explorer 11 in Compatibility Mode Look to the right side edge of the Internet Explorer window. Put Internet Explorer 10 in Compatibility Mode Look to the right side of the address bar at the top of the Internet Explorer window. In the second term it appears that we are using the following function, and this has been shifted by the correct amount.
With these functions identified we can now take the transform of the function. So H(s) and its inverse transform is, Now, lets go back to the original problem, remembering to multiply the transform through the parenthesis. My first priority is always to help the students who have paid to be in one of my classes here at Lamar University (that is my job after all!). These often do not suffer from the same problems. So, while I'd like to answer all emails for help, I can't and so I'm sorry to say that all emails requesting help will be ignored. Now use the substitution u = t c and the integral becomes, The second exponential has no us in it and so it can be factored out of the integral. Close the Menu The following list of questions/complaints about this site I am constantly getting emails about so I decided to put the answers to them here in a effort to get them answered quicker. From our table of Laplace transforms we have #16 and using that we can see that if This will make our life a little easier so well do it this way. The following function will exhibit this kind of behavior.